Input a number and check it is an armstrong number or not using while loop in C++
while Loop - Question 15
In this question, we will see how to input a number and check if it is an armstrong numbers or not in C++ programming using while loop. To know more about while loop click on the while loop lesson.
Q15) Write a program in C++ to input a number and check if it is an armstrong numbers or not using while loop.
An Armstrong number is a number whose sum of cube of the digits is equal to the original number. Example 153 = 13 + 53 + 33
Program
#include <iostream>
#include <conio.h>
using namespace std;
int main()
{
int n,d,on,soc=0;
cout<<"Enter any number ";
cin>>n;
on=n; // storing the original number
while(n>0)
{
d=n%10;
soc=soc+(d*d*d); // sum of cube of the digits
n=n/10;
}
if(on==soc)
{
cout<<"Armstrong Number";
}
else
{
cout<<"Not Armstrong Number";
}
return 0;
}Output
Enter any number 153 Armstrong Number
